How do I start in solving 6sinx = 5 - 8cosx????

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- Aug 22nd 2008, 10:58 PMxwrathbringerxtrigonometric equation
How do I start in solving 6sinx = 5 - 8cosx????

- Aug 22nd 2008, 11:26 PMticbol
- Aug 23rd 2008, 01:16 AMxwrathbringerxQuote:

One way is you use sin(x) = sqrt[1 -cos^2(x)].

Another way is you use cos(x) = sqrt[1 -sin^2(x)].

Or, just square both sides of the posted equation.

- Aug 23rd 2008, 01:22 AMxwrathbringerx
oh no w8 solved it (Rofl)

squared it wrong