part (a)
solve for x, the horizontal distance.
part (b)
solve for z, the distance the airplane must fly to reach the runway.
Ok. I missed class today so didnt quite get the lesson via math tutorial.
The question is:
When a 757 passenger jet begins its descent to the Ronald Reagan International Airport in Dc, it is 3900 ft from the ground. its angle od descent is 6 degrees.
a. what is the plane's ground distance to the airport?
b. how far must the plane fly to reach the runway?
idk how to do it from the tutorial this is what i did....
cos 6 = 3900
6 = 3921.5
is that how im suppose to folllow thru and do?
please any suggestions
Hello, topaz192!
First, make a good sketch.When a passenger jet begins its descent to the airport,
it is 3900 ft from the ground. Its angle of descent is 6°.Code:A * - - - - - - - - - - - H : * 6° : * 3900 : * : * : 6° * B * - - - - - - - - - - - * C
The jet is at A. . feet. .The airport is at
We want distancea) What is the plane's ground distance to the airport?
In right triangle
Therefore: .
We want distanceb) How far must the plane fly to reach the runway?
In right triangle
Therefore: .