Hello, The Real Cosby!

You should be familiar with the "Rotation" formulas.

Otherwise, you shouldnothave been assigned this problem.

The general quadratic equation is: .

We have: .

1. Find and

Formula: .

We have: .

Since is in Quadrant 2: .

is in a right triangle with:

Using Pythagorus, we get: .

Therefore: .

Since is in Quadrant 2, then is in Quadrant 1.2. Find and

Identities: .

We have: .

Formulas: .3. Transform the equation xy=1 by rotation, . ??

. . thus eliminating the xy term.

We have: .

Substitute into [1]: .

. .

. .

. .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Drat! .I just figured out what #3 meant . . .

It is a!separate problem

We have: .

. . That is: .

. . It is a hyperbola rotated through 45°.

Hence: .

Substitute into [2]: .

. . Therefore: .

I need a nap . . .

.