evaluate sin (arccos x) , 0 < x< 1
Hello, cruxkitty!
Recall that an inverse trig expression is an angle.. They meant to say "Simplify".
. . . . . . angle whose cosine is x
"The angle whose cosine is " looks like this:Code:* * * 1 * * ____ * * √1-x² * * * θ * * * * * * * * x
From Pythagorus, we find that: .
Hence: .
Therefore: .