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Math Help - one more please help

  1. #1
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    one more please help

    I am have a great deal of trouble solving for x for some reason. Can someone please show me the steps involved in solving this problem.
    solve for X: y=2sin3x
    thanx
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by whiteowl View Post
    I am have a great deal of trouble solving for x for some reason. Can someone please show me the steps involved in solving this problem.
    solve for X: y=2sin3x
    thanx
    Divide through by 2:

    \frac{y}{2}=\sin(3x)

    take the inverse sine of both sides:

    \sin^{-1}\left(\frac{y}{2}\right)=\sin^{-1}\left(\sin(3x)\right)\implies <br />
\sin^{-1}\left(\frac{y}{2}\right)=3x

    I'm sure you can take it from here.

    --Chris
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  3. #3
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    Thanx, It all looks simple when I see it but for somereason could not make myself do it that way. Thanx again
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