I am have a great deal of trouble solving for x for some reason. Can someone please show me the steps involved in solving this problem.
solve for X: y=2sin3x
thanx

2. Originally Posted by whiteowl
I am have a great deal of trouble solving for x for some reason. Can someone please show me the steps involved in solving this problem.
solve for X: y=2sin3x
thanx
Divide through by 2:

$\frac{y}{2}=\sin(3x)$

take the inverse sine of both sides:

$\sin^{-1}\left(\frac{y}{2}\right)=\sin^{-1}\left(\sin(3x)\right)\implies
\sin^{-1}\left(\frac{y}{2}\right)=3x$

I'm sure you can take it from here.

--Chris

3. Thanx, It all looks simple when I see it but for somereason could not make myself do it that way. Thanx again