given that z =cosθ +jsinθ ((zē-1)/(zē+1))=jtanθ Can someone prove it to mi pls. THX
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can any1 pls help mi???? i nid help
Originally Posted by juzo given that z =cosθ +jsinθ ((zē-1)/(zē+1))=jtanθ Can someone prove it to mi pls. THX Substitute for z in numerator and denominator and expand. Substitute and . Simplify:
Originally Posted by mr fantastic Substitute for z in numerator and denominator and expand. Substitute and . Simplify: Sry, i dun get the first line. can u show a bit more of the steps of the first part
Originally Posted by juzo Sry, i dun get the first line. can u show a bit more of the steps of the first part Did you substitute ? Did you expand? Did you substitute and ? Please show your working and where you get stuck.
Given that z=cosθ+jsinθ show that ((cos2θ+sin2θ-1)/(cos2θ+sin2θ+1)) den i dunno sub wht inside to get correct
Hello, juzo! I have a looong proof . . . hope someone finds a shorter one! Given: . Prove: . Using DeMoivre's Theorem, we have: . . . . So we have: . Rationalize: . . . . . . . . .
Originally Posted by juzo Given that z=cosθ+jsinθ show that ((cos2θ+sin2θ-1)/(cos2θ+sin2θ+1)) den i dunno sub wht inside to get correct I was expecting to see By the way, please try to use proper English, NOT den, dunno, wht, mi pls etc. (which I personally find very annoying).
Let this means . Thus,
Originally Posted by ThePerfectHacker Let this means . Thus, Good post, but it's likely that juzo won't have done complex analysis to this level. Like Mr Fantastic says, substitute into the equation. So Then the rest of Mr Fantastic's work follows. Hope that helped.
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