# Math Help - Verifying Trigonometric Identities, HELP!!!

1. ## Verifying Trigonometric Identities, HELP!!!

HEEEEEEEEELP!!!

sinX/(1-cosX) - sinXcosX/(1+cosX) = cscX(1+cossquaredX)

nee

2. One good strategy is to try to get the complicated side equal to the simpler side.

$\frac{\sin{x}}{1-\cos{x}} - \frac{\sin{x}\cos{x}}{1+\cos{x}} = \csc{x}(1+\cos^2{x})$

$\frac{\sin{x}(1+\cos{x})}{1-\cos^2{x}} - \frac{\sin{x}\cos{x}(1-\cos{x})}{1-\cos^2{x}}$

$\frac{\sin{x}(1+\cos{x})}{\sin^2x} - \frac{\sin{x}\cos{x}(1-\cos{x})}{\sin^2{x}}$

$\frac{(1+\cos{x})}{\sin{x}} - \frac{\cos{x}(1-\cos{x})}{\sin{x}}$

$\frac{1+\cos{x} - \cos{x}(1-\cos{x})}{\sin{x}}$

$\frac{1+\cos{x} - \cos{x}+\cos^2{x}}{\sin{x}}$

$\frac{1+\cos^2{x}}{\sin{x}} = \csc{x}(1+\cos^2{x})$

3. Wow awsom thanks alot!!!