1. ## trig equation

how do i solve for an exact answer for
0= sinx + xcosx on interval [0,2pi]
i got (tanx)/x = -1 but that doesnt really help me

2. Originally Posted by zintore
how do i solve for an exact answer for
0= sinx + xcosx on interval [0,2pi]
i got (tanx)/x = -1 but that doesnt really help me
You're not going to get exact answers...>_>

You'll have to approximate them.

You'll get 3 values that fall in the domain [0,2Pi] : x=0, 2.02875783811 and 4.91318043943

I hope this helps!

--Chris

EDIT: I got the values for x by solving the equation tan(x)=-x...