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**pistonsfan22** Okay so I still have no idea how I got this problem wrong on a test. I have the Unit Circle memorized (radians, degrees, and the cosine & sine cordinates)

I know that when you deal with wrapping functions you are really just taking the cosine (x) coordinate on a unit circle and sin (y) coordinate on a unit circle of what ever P( ) which means P of ( ) whatever #.

How is P of (-pi/6) written as P(-pi/6) equal to (-sq root of 3/2,-1/2)

This problem is really just pissing me off. First of all I know that -pi/6 in degrees is 30 and negative 30 degrees is in the IV quadrant so how can the answer be neg sq root of 3/2, -1/2.

On the test I put positive sq root of 3/2, -1/2 and got it wrong.

Help help help!!!

Wrapping functions piss me off!!!