Trig help Wrapping Function
Okay so I still have no idea how I got this problem wrong on a test. I have the Unit Circle memorized (radians, degrees, and the cosine & sine cordinates)
I know that when you deal with wrapping functions you are really just taking the cosine (x) coordinate on a unit circle and sin (y) coordinate on a unit circle of what ever P( ) which means P of ( ) whatever #.
How is P of (-pi/6) written as P(-pi/6) equal to (-sq root of 3/2,-1/2)
This problem is really just pissing me off. First of all I know that -pi/6 in degrees is 30 and negative 30 degrees is in the IV quadrant so how can the answer be neg sq root of 3/2, -1/2.
On the test I put positive sq root of 3/2, -1/2 and got it wrong.
Help help help!!!
Wrapping functions piss me off!!!