1. ## Help

I need to solve for y in terms of "n" in the following:

cosh(ny)=n+.5

Any body have any ideas?

2. Originally Posted by rman144
I need to solve for y in terms of "n" in the following:

cosh(ny)=n+.5

Any body have any ideas?
Apply the inverse hyperbolic cosine to both sides:

$\cosh^{-1}\left(\cosh(ny)\right)=\cosh^{-1}(n+.5)$

$\implies y=\frac{1}{n}\cosh^{-1}\left(n+.5\right)$.

Is this what you're looking for?

--Chris