I need to solve for y in terms of "n" in the following: cosh(ny)=n+.5 Any body have any ideas?

Last edited by rman144; Jul 20th 2008 at 10:02 PM. Reason: Dumb

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Originally Posted by rman144 I need to solve for y in terms of "n" in the following: cosh(ny)=n+.5 Any body have any ideas? Apply the inverse hyperbolic cosine to both sides: $\displaystyle \cosh^{-1}\left(\cosh(ny)\right)=\cosh^{-1}(n+.5)$ $\displaystyle \implies y=\frac{1}{n}\cosh^{-1}\left(n+.5\right)$. Is this what you're looking for? --Chris