Originally Posted by

**fardeen_gen** Let the two triangles formed be ABC and ABC'. [both right angled at B]

ACB = 60 degrees, AC'B = 45 degrees.

Let AB = h, BC = x (therefore, CC' = 30)

Now in triangle ABC,

tan 60 = AB/BC

(or) tan 60 = h / x

(or) sqrt(3) = h / x

(or) x = h / sqrt(3) --------- I

In triangle ABC',

tan 45 = AB / AC'

(or) 1 = h / (AC + CC')

(or) 1 = h / (x + 30)

** (or) h = x + 30 **

(or) h = h/sqrt(3) + 30 --------using I

(or) h = [30*sqrt(3)]/[sqrt(3) - 1]

Therefore height of the minar is (30*1.73)/(0.73) m.