
Originally Posted by
fardeen_gen
Let the two triangles formed be ABC and ABC'. [both right angled at B]
ACB = 60 degrees, AC'B = 45 degrees.
Let AB = h, BC = x (therefore, CC' = 30)
Now in triangle ABC,
tan 60 = AB/BC
(or) tan 60 = h / x
(or) sqrt(3) = h / x
(or) x = h / sqrt(3) --------- I
In triangle ABC',
tan 45 = AB / AC'
(or) 1 = h / (AC + CC')
(or) 1 = h / (x + 30)
(or) h = x + 30
(or) h = h/sqrt(3) + 30 --------using I
(or) h = [30*sqrt(3)]/[sqrt(3) - 1]
Therefore height of the minar is (30*1.73)/(0.73) m.