Can someone help me with these two?

**Dave53** · July 14th 2008, 05:07 PM

Change the following polar equation to rectangular form.

r=cotΘ

Find a polar equation of the conic with focus at the pole and the given eccentricity and directrix.

e=3/2,ysinΘ=1

Thanks again for the help!

Dave

**topsquark** · July 14th 2008, 05:43 PM

Originally Posted by Dave53

Change the following polar equation to rectangular form.

r=cotΘ

$r = cot(\theta)$

$r = \frac{cos(\theta)}{sin(\theta)}$

$r~sin(\theta) = cos(\theta)$

Now,
$y = r~sin(\theta)$
and
$x = r~cos(\theta) \implies cos(\theta) = \frac{x}{r} = \frac{x}{\sqrt{x^2 + y^2}}$

So
$y = \frac{x}{\sqrt{x^2 + y^2}}$

-Dan

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Can someone help me with these two?