find exact value of cos[tan-1(-1)+cos-1(-3/5)]

tan-1 is inverse tan

cos-1 is inverse cos

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- July 8th 2008, 11:52 AMdavis16this problem is hard see if you can help me out
find exact value of cos[tan-1(-1)+cos-1(-3/5)]

tan-1 is inverse tan

cos-1 is inverse cos - July 8th 2008, 11:59 AMTKHunny
Here we are again. Have you done a, b, and d on the last one, yet?

For this one, you also need this formula, which you should know.

cos(a+b) = cos(a)cos(b)-sin(a)sin(b)

After that, you'll need those Right Triangles again. - July 9th 2008, 11:12 AMdavis16
still need help. atleast tell me how to start

- July 9th 2008, 12:02 PMflyingsquirrel
- July 9th 2008, 02:25 PMTKHunny
You have posted seven (7) problems in four (4) posts. You have not shown ANY work at all. You have provided NO feedback to indicate whether you are learning anything. So far, you have managed to get others to do your homework for you. This will NOT serve you well on an examination. What's it going to be? Learning or just laziness? I can be harsh if you would like. So far, I'm just trying to get your attention. You WILL fail your class if you keep on this way. Pick a different path. Sooner is better.

- July 10th 2008, 12:31 AMMoo
- July 10th 2008, 12:45 AMflyingsquirrel
- July 10th 2008, 12:48 AMMoo
Yes, you're right :D