Thread: Just need confirmation on a circular function question.

determine the value of the following if 0 is less than or equal to theta and theta is less than 2 pie.

sec theta= -2root3/3= -root/3= 7pie/6

Originally Posted by Dave19

determine the value of the following if 0 is less than or equal to theta and theta is less than 2 pie.

sec theta= -2root3/3= -root/3= 7pie/6

First, it's "pi" not "pie."

Second, what exactly are you asking? These cannot all be equal to one another.

Are you asking to find when




and to find


You've been asking for help on a large number of these. Why don't you tell us what you've been able to do so we can help you learn this better.

-Dan

i will put it in steps 1,2,3,4


sec theta= 1)-2root3/3 2) cos theta=1/sec theta 3) after the work it turns to -root3/2 4) then i have it as 7pie/6 and im unsure if there should be 5pie/6 in it to.

Originally Posted by Dave19

i will put it in steps 1,2,3,4


sec theta= 1)-2root3/3 2) cos theta=1/sec theta 3) after the work it turns to -root3/2 4) then i have it as 7pie/6 and im unsure if there should be 5pie/6 in it to.

Okay, please in the future don't string those equal signs together like that. It is very confusing!





Now, this implies that we have a reference angle of . Cosine is negative in QII and QIII. So your solution will be

so your final solution is both and .

-Dan