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Math Help - finding the value of theta to the nearest second.

  1. #1
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    finding the value of theta to the nearest second.

    1) sin theta= -0.4545 and theta is in the 4th quadrant



    2) sec theta= 2/3 and theta is in 1st quadrant
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  2. #2
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    1. sin(theta) = -0.4545 = - 4545/10000 = - 909/2000 (reduce it to lowest terms)
    You have to first express it in terms of a fraction.

    sin(theta) = y/r

    So you got y and you got r. Since theta is in 4th quadrant, x is positive and y is negative. Use the Pythagorean theorem to find x and choose the positive root, then replace in cos(theta) = x/r

    x^2 + y^2 = r^2

    2. Sec is the reciprocal for cos. So if cos(theta) = x/r, then sec(theta) = r/x. You know how to continue.
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  3. #3
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    chop suey

    is that the only way to do it and if it is for the first one is the answer around 1700.
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  4. #4
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    Well, that's the way I know. And show me what you have done so far. What answer?
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  5. #5
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    x squared= 3 173 719= 1781.49
    ya i think im lost and also what does it mean by nearest second do you have to put it in degrees minutes and seconds
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