1) sin theta= -0.4545 and theta is in the 4th quadrant

2) sec theta= 2/3 and theta is in 1st quadrant

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- Jul 6th 2008, 07:19 AMDave19finding the value of theta to the nearest second.
1) sin theta= -0.4545 and theta is in the 4th quadrant

2) sec theta= 2/3 and theta is in 1st quadrant - Jul 6th 2008, 07:40 AMChop Suey
1. sin(theta) = -0.4545 = - 4545/10000 = - 909/2000 (reduce it to lowest terms)

You have to first express it in terms of a fraction.

sin(theta) = y/r

So you got y and you got r. Since theta is in 4th quadrant, x is positive and y is negative. Use the Pythagorean theorem to find x and choose the positive root, then replace in cos(theta) = x/r

x^2 + y^2 = r^2

2. Sec is the reciprocal for cos. So if cos(theta) = x/r, then sec(theta) = r/x. You know how to continue. - Jul 6th 2008, 07:50 AMDave19chop suey
is that the only way to do it and if it is for the first one is the answer around 1700.

- Jul 6th 2008, 08:00 AMChop Suey
Well, that's the way I know. And show me what you have done so far. What answer?

- Jul 6th 2008, 08:04 AMDave19
x squared= 3 173 719= 1781.49

ya i think im lost and also what does it mean by nearest second do you have to put it in degrees minutes and seconds