determine the value of the following if 0 is less than or equal to theta and theta is less than 2 pie. - sin theta= -1 -sec theta= -2root3/3
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1)-sinx=-1 sinx=1 x=pi/2 2)-secx=-[2((3)^1/2)]/3 secx=2/3^1/2 cosx=[3^1/2]/2 cosx=cos(pi/6) x=pi/6,11pi/6 NOTE: sinA=sinB THEN A=n(pi)+((-1)^n)B n is any integer. cosA=cosB THEN A=2n(pi)+-B +-=plus minus n is any integer
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