
Tan on a unit circle
Hi again!
I've solved a trig problem and now I have tanx=pi/3, which i know is equal to $\displaystyle \sqrt{3}$.
Im struggling with putting this on a unit circle so I can solve for all of the possible angles. I would appreciate if someone could show me on a unit circle where the possible x's are for this and how i could find out the various angles (of which there are 4).
Thanks,
Steven

$\displaystyle \displaystyle\tan\frac{\pi}{3}=\sqrt{3}$, not $\displaystyle \tan\sqrt{3}=\frac{\pi}{3}$
Probably the equation is $\displaystyle \tan x=\sqrt{3}$
In this case all solutions are $\displaystyle x=\frac{\pi}{3}+k\pi, \ k\in\mathbf{Z}$

There are two special triangles you can use to find out the trigonometric ratios of the angles: 30, 45, and 60; the 454590 triangle and the 306090 triangle.
Special right triangles  Wikipedia, the free encyclopedia