OK so the other day Reckoner gave me some great help with these, but now i can't work out this one. What's really confused me is the $\displaystyle x-pi/3$ in the middle. I know the answer should be over 6 (as in like $\displaystyle pi/6$) but I can't work out how the bit in the middle comes into play. Would you do this...

$\displaystyle sinx-sin*pi/3=1/2

sinx=1/2 + sin*3

$

etc.....????????????????????