Hey guys i want to know if i am correct here
let y=arctan(-5/12)
sec y= 13/12 or 65 degrees
is this correct
If y = arctan(-5 /12),
then, tan(y) = -5/ 12
So, y is an angle whose tan value is -5 /12.
tan = (opposite side)/(adjacent side) = opp/adj
So, for angle y above,
opp = -5
adj = 12
The hypotenuse---hyp---then is sqrt[(-5)^2 +(12)^2] = 13
sec = hyp/adj
So, sec(y) = 13/12 -----you got that right.
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If y = arctan(5/(-12)),
Then, opp = 5, adj = -12, hyp = 13
sec(y) = 13/(-12) or -(13/12)