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June 30th 2008, 03:00 PM
NoAsherelol

Need help finding solutions

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Tan^2 x + Tan x = 0

im having extreme difficulty with this problems
June 30th 2008, 03:25 PM
Soroban

Hello, NoAsherelol!

Did you forget your basic algebra?

Quote:

Find all solutions: . $\tan^2\!x + \tan x \:= \:0$

Factor: . $\tan x(\tan x + 1) \:=\:0$

Then we have: . $\tan x \:=\:0\quad\Rightarrow\quad x \:=\:\pi n$

And: . $\tan x + 1 \:=\:0\quad\Rightarrow\quad \tan x \:=\:-1\quad\Rightarrow\quad x \:=\:\frac{3\pi}{4} + \pi n$

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