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Math Help - [SOLVED] Double Angle Identities

  1. #1
    Junior Member Evales's Avatar
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    [SOLVED] Double Angle Identities

    I have to make use of:
    sin2x = 2sinxcosx
    cos2x = cos^2x - sin^2x
    sin3x = 3sinx - 4sin^3x
    cos3x = 4cos^3x - 3cosx

    In order to prove:
    sin3x = 4sinxcos^2x - sinx
    sin4x = 8sinxcos^3x - 4sinxcosx
    ect.

    It looks like they are connected but I just can't see how they are connected.
    Below is some of my working.

    sin3x = 4sinxcos^2x - sinx
    RHS = 2(2sinxcosx)cosx - sinx
    RHS = (sin2x)2cosx - sinx

    I am then promptly stumped

    Should I be working with LHS, what sort of substitutions should I be doing?
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  2. #2
    Moo
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    A Cute Angle Moo's Avatar
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    Hello,

    Quote Originally Posted by Evales View Post
    I have to make use of:
    sin2x = 2sinxcosx
    cos2x = cos^2x - sin^2x
    sin3x = 3sinx - 4sin^3x
    cos3x = 4cos^3x - 3cosx

    In order to prove:
    sin3x = 4sinxcos^2x - sinx
    sin4x = 8sinxcos^3x - 4sinxcosx
    ect.

    It looks like they are connected but I just can't see how they are connected.
    Below is some of my working.

    sin3x = 4sinxcos^2x - sinx
    RHS = 2(2sinxcosx)cosx - sinx
    RHS = (sin2x)2cosx - sinx

    I am then promptly stumped

    Should I be working with LHS, what sort of substitutions should I be doing?
    Hmm for \sin(3x), you can study both the RHS or the LHS.

    RHS=4sinxcos^2x-sinx=sinx(4cos^2x-1)

    But we know that cos^2x=1-sin^2x

    --> RHS=sinx(4(1-sin^2x)-1)=sinx(4-4sin^2x-1)= sinx(3-4sin^2x)=3sinx-4sin^3x=sin(3x)


    I guess it will be the same method for sin(4x) : juggle with the given elements and the basic properties
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  3. #3
    Junior Member bleesdan's Avatar
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    You may also need trigonometric sum formulas.
    I'm fishy on how to add Latex in a forum post, so you get a link!
    Trigonometric Addition Formulas -- from Wolfram MathWorld

    Then, note that sin(3x)=sin(x+2x)
    Mess with the LHS, and remember all of your identities!!!
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  4. #4
    Junior Member Evales's Avatar
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    Yeh my teacher was saying that I can do it using only the identities given but I ended up using 1 = sin^2x + cos^2x Thanks a bunch guys!
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  5. #5
    Flow Master
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    Quote Originally Posted by bleesdan View Post
    You may also need trigonometric sum formulas.
    I'm fishy on how to add Latex in a forum post, so you get a link!
    Trigonometric Addition Formulas -- from Wolfram MathWorld

    Then, note that sin(3x)=sin(x+2x)
    Mess with the LHS, and remember all of your identities!!!
    Any 'messing' to be done happens on the RHS (Right Hand Side).
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  6. #6
    Senior Member nikhil's Avatar
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    Strategy

    Hi!Evales,hope ur having a great time.
    RHS side of the identity is in single angle form and the LHS is in a multiple angle form. Main objective is to convert multiple angle to single angle.
    You may use addition formula for example sin3x=sin(x+2x),
    sin4x=sin(3x+x) or sin(2x+2x).when you will expand them,the expansion will involve multiple angle(2x or 3x) now again use addition formula to convert the multiple angle to single angle.keep on doing this until all multiple angles are converted into single angle.
    NOTE:conversly single angle can also be converted into multiple angle eg sinx=sin(2x-x) or sin(3x-2x) etc.
    Hope this will help.
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