How does$\displaystyle sin\frac{7pi}{12} = sin(\frac{Pi}{4} +\frac{Pi}{3})$ Do you find factors of 12 which are 3 and 4? What do you do with the $\displaystyle 7pi$? Thanks Jason
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Originally Posted by Darkhrse99 How does$\displaystyle sin\frac{7pi}{12} = sin(\frac{Pi}{4} +\frac{Pi}{3})$ Do you find factors of 12 which are 3 and 4? What do you do with the $\displaystyle 7pi$? Thanks Jason $\displaystyle \sin\left(\frac{7\pi}{12}\right)=\sin\left(\frac{3 \pi+4\pi}{12}\right)=\sin\left(\frac{3\pi}{12}+\fr ac{4\pi}{12}\right)=\color{red}\boxed{\sin\left(\f rac{\pi}{4}+\frac{\pi}{3}\right)}$ Does this make sense? --Chris
that was easy! I can't believe I didn't see that
Last edited by ThePerfectHacker; Jul 10th 2008 at 11:29 AM.
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