Solve the equation: , in the interval Please help me on how to simplify this equation in the exam (any techniques?). Thanks!
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Originally Posted by rednest Solve the equation: , in the interval Please help me on how to simplify this equation in the exam (any techniques?). Thanks! i suggest you may start with..
Here's what I did. I'm pretty sure it's right: We have- First: Next: Keep in mind that Then: Now we remember that: Therefore: So: Negatives can cancel, giving us: Now, we go to another identity: So: Now: And finally: And there you go.
Originally Posted by Aryth Now: And finally: And there you go. we cannot do this immediately, since can be zero (and pi) and so does .. so, the best way is to do this: .. and there you go.. and also after finding the values of , try to check whether it fits the original equation..
Last edited by kalagota; June 23rd 2008 at 01:05 AM.
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