Thread: Will someone check my triq answers please!

1. Will someone check my triq answers please!

I'm finding the exact values of the following expressions.

1. $\displaystyle sin(\frac{-7pi} {3})$ = $\displaystyle \frac{\sqrt3}{2}$

2. $\displaystyle sec(\frac{-21pi}{4})$= $\displaystyle \frac{-\sqrt1}{2}$

3. $\displaystyle cot(\frac{25pi}{2})$=Undefined

4. $\displaystyle csc(\frac{-101pi}{6})$= $\displaystyle -1$

5.$\displaystyle cos({-126Pi})$= Undefined

Thank You
Jason

2. Originally Posted by Darkhrse99
I'm finding the exact values of the following expressions.

1. $\displaystyle sin(\frac{-7p} {3})$ = $\displaystyle \frac{\sqrt3}{2}$ << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative

2. $\displaystyle sec(\frac{-21p}{4})$= $\displaystyle \frac{-\sqrt1}{2}$ << SiMoon says : it's rather $\displaystyle -\sqrt{\frac 12}=-\frac{2}{\sqrt{2}}$ eh ? Check the code =)

3. $\displaystyle cot(\frac{25p}{2})$=Undefined << SiMoon says : is 0 undefined ? $\displaystyle \cot=\frac{\cos}{\sin} \quad \quad \frac{25 \pi}{2}=6*(2 \pi)+ \frac{\pi}{2}$ ---> ...

4. $\displaystyle csc(\frac{-101p}{6})$= $\displaystyle -1$ << SiMoon says : I find -2

5.$\displaystyle cos({-126P})$= Undefined << SiMoon says : I find 1

Thank You
Jason

3. Originally Posted by Darkhrse99
I'm finding the exact values of the following expressions.

1. = << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative. Chris says it's in the 4th quadrant. -7pi/3=-2pi-pi/3 -----> sine is still negative (As Moo correctly stated)

2. = << SiMoon says : it's rather eh ? Check the code =)

3. =Undefined << SiMoon says : is 0 undefined ? ---> ...

4. = << SiMoon says : I find -2.

5.= Undefined << SiMoon says : I find 1

Thank You
Jason

4. Originally Posted by Chris L T521

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Like I said, $\displaystyle 7=3+1$ !!!

Hey, how did you quote what I quoted ?

5. Originally Posted by Moo
Like I said, $\displaystyle 7=3+1$ !!!

Hey, how did you quote what I quoted ?
What I did was a little something called copy and paste.

When I quoted you to post my response. I saw just this :

However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...

6. Originally Posted by Chris L T521
What I did was a little something called copy and paste.

When I quoted you to post my response. I saw just this :

However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...
When I copy & paste, it doesn't copy the latex stuff

7. For #2. the point are$\displaystyle -\frac{\sqrt1}{2} and \frac{1}{2} = \frac{1}{y}$ Which gives the answer $\displaystyle \frac{-\sqrt1}{2}$, Right?

8. I don't see how you get -2 for the 2nd problem?