Will someone check my triq answers please!

**Darkhrse99** · June 18th 2008, 11:33 AM

I'm finding the exact values of the following expressions.

1. $sin(\frac{-7pi} {3})$ = $\frac{\sqrt3}{2}$

2. $sec(\frac{-21pi}{4})$ = $\frac{-\sqrt1}{2}$

3. $cot(\frac{25pi}{2})$ =Undefined

4. $csc(\frac{-101pi}{6})$ = $-1$

5. $cos({-126Pi})$ = Undefined

Thank You
Jason

**Moo** · June 18th 2008, 11:41 AM

Originally Posted by Darkhrse99

I'm finding the exact values of the following expressions.

1. $sin(\frac{-7p} {3})$ = $\frac{\sqrt3}{2}$ << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative

2. $sec(\frac{-21p}{4})$ = $\frac{-\sqrt1}{2}$ << SiMoon says : it's rather $-\sqrt{\frac 12}=-\frac{2}{\sqrt{2}}$ eh ? Check the code =)

3. $cot(\frac{25p}{2})$ =Undefined << SiMoon says : is 0 undefined ? $\cot=\frac{\cos}{\sin} \quad \quad \frac{25 \pi}{2}=6*(2 \pi)+ \frac{\pi}{2}$ ---> ...

4. $csc(\frac{-101p}{6})$ = $-1$ << SiMoon says : I find -2

5. $cos({-126P})$ = Undefined << SiMoon says : I find 1

Thank You
Jason

**Chris L T521** · June 18th 2008, 11:49 AM

Originally Posted by Darkhrse99

I'm finding the exact values of the following expressions.

1. = << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative. Chris says it's in the 4th quadrant. -7pi/3=-2pi-pi/3 -----> sine is still negative (As Moo correctly stated)

2. = << SiMoon says : it's rather eh ? Check the code =)

3. =Undefined << SiMoon says : is 0 undefined ? ---> ...

4. = << SiMoon says : I find -2.

5.= Undefined << SiMoon says : I find 1

Thank You
Jason

**Moo** · June 18th 2008, 11:53 AM

Originally Posted by Chris L T521

[/I]

Like I said, $7=3+1$ !!!

Hey, how did you quote what I quoted ?

**Chris L T521** · June 18th 2008, 11:55 AM

Originally Posted by Moo

Like I said, $7=3+1$ !!!

Hey, how did you quote what I quoted ?

What I did was a little something called copy and paste.

When I quoted you to post my response. I saw just this :

However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...

**Moo** · June 18th 2008, 12:03 PM

Originally Posted by Chris L T521

What I did was a little something called copy and paste.

When I quoted you to post my response. I saw just this :

However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...

When I copy & paste, it doesn't copy the latex stuff

**Darkhrse99** · June 18th 2008, 12:08 PM

For #2. the point are $-\frac{\sqrt1}{2} and \frac{1}{2} = \frac{1}{y}$ Which gives the answer $\frac{-\sqrt1}{2}$ , Right?

**Darkhrse99** · June 18th 2008, 03:31 PM

I don't see how you get -2 for the 2nd problem?

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