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Thread: Will someone check my triq answers please!

  1. #1
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    Will someone check my triq answers please!

    I'm finding the exact values of the following expressions.

    1. $\displaystyle sin(\frac{-7pi} {3})$ = $\displaystyle \frac{\sqrt3}{2}$

    2. $\displaystyle sec(\frac{-21pi}{4})$= $\displaystyle \frac{-\sqrt1}{2}$

    3. $\displaystyle cot(\frac{25pi}{2})$=Undefined

    4. $\displaystyle csc(\frac{-101pi}{6})$= $\displaystyle -1$

    5.$\displaystyle cos({-126Pi})$= Undefined



    Thank You
    Jason
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  2. #2
    Moo
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    Quote Originally Posted by Darkhrse99 View Post
    I'm finding the exact values of the following expressions.

    1. $\displaystyle sin(\frac{-7p} {3})$ = $\displaystyle \frac{\sqrt3}{2}$ << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative

    2. $\displaystyle sec(\frac{-21p}{4})$= $\displaystyle \frac{-\sqrt1}{2}$ << SiMoon says : it's rather $\displaystyle -\sqrt{\frac 12}=-\frac{2}{\sqrt{2}}$ eh ? Check the code =)

    3. $\displaystyle cot(\frac{25p}{2})$=Undefined << SiMoon says : is 0 undefined ? $\displaystyle \cot=\frac{\cos}{\sin} \quad \quad \frac{25 \pi}{2}=6*(2 \pi)+ \frac{\pi}{2}$ ---> ...

    4. $\displaystyle csc(\frac{-101p}{6})$= $\displaystyle -1$ << SiMoon says : I find -2

    5.$\displaystyle cos({-126P})$= Undefined << SiMoon says : I find 1



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    Jason
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  3. #3
    Rhymes with Orange Chris L T521's Avatar
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    Originally Posted by Darkhrse99
    I'm finding the exact values of the following expressions.

    1. = << SiMoon says : eh.. -7pi/3=-pi-pi/3, that is to say it's in the 3rd quadrant ---> sine is negative. Chris says it's in the 4th quadrant. -7pi/3=-2pi-pi/3 -----> sine is still negative (As Moo correctly stated)

    2. = << SiMoon says : it's rather eh ? Check the code =)

    3. =Undefined << SiMoon says : is 0 undefined ? ---> ...

    4. = << SiMoon says : I find -2.

    5.= Undefined << SiMoon says : I find 1



    Thank You
    Jason



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  4. #4
    Moo
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    Quote Originally Posted by Chris L T521 View Post

    [/I]
    Like I said, $\displaystyle 7=3+1$ !!!


    Hey, how did you quote what I quoted ?
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  5. #5
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by Moo View Post
    Like I said, $\displaystyle 7=3+1$ !!!


    Hey, how did you quote what I quoted ?
    What I did was a little something called copy and paste.

    When I quoted you to post my response. I saw just this :

    However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...
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  6. #6
    Moo
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    Quote Originally Posted by Chris L T521 View Post
    What I did was a little something called copy and paste.

    When I quoted you to post my response. I saw just this :

    However, I thought I could copy what you quoted and then put it in the quote tags...and it worked...
    When I copy & paste, it doesn't copy the latex stuff
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  7. #7
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    For #2. the point are$\displaystyle -\frac{\sqrt1}{2} and \frac{1}{2} = \frac{1}{y}$ Which gives the answer $\displaystyle \frac{-\sqrt1}{2}$, Right?
    Last edited by Darkhrse99; Jun 18th 2008 at 12:39 PM.
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  8. #8
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    I don't see how you get -2 for the 2nd problem?
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