solve the following system of equations algebraically (-2π, 2π) y=cos^2 (x) y=sin^2 (x) + 1/2 please show all work Thanks
Last edited by meli3000; Jun 13th 2008 at 05:32 PM. Reason: missed part
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Cos^2(x) = Sin^2(x) + 1/2 Cos^2(x) - Sin^2(x) = 1/2 Cos(2x) = 1/2 2x = Cos^-1(1/2) x = (Cos^-1(1/2))/2
In fact, it's... pi/6, 5pi/6, -pi/6, -5pi/6
Last edited by sean.1986; Jun 13th 2008 at 06:11 PM.
Hello, meli3000! Solve the following system of equations algebraically . . . . Substitute into [1]: . . .
Ah yeah forgot that because it's double you get 2 more answers. Oops!
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