Having trouble with this problem....

Establish the Identity:

(sec^2t)-(csc^2t)=csc^2t(sec^2t-2)

and this ones seems easy but im not sure...

Find the exact Value:

csc(tan^-1)(-.5)

hummm,

Thanks if anyone can help!

Results 1 to 6 of 6

- Jun 3rd 2008, 11:26 AM #1

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- May 2008
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## Problem Help

Having trouble with this problem....

Establish the Identity:

(sec^2t)-(csc^2t)=csc^2t(sec^2t-2)

and this ones seems easy but im not sure...

Find the exact Value:

csc(tan^-1)(-.5)

hummm,

Thanks if anyone can help!

- Jun 3rd 2008, 11:49 AM #2

- Jun 3rd 2008, 11:53 AM #3

- Jun 3rd 2008, 06:52 PM #4

- Joined
- May 2008
- Posts
- 10

- Jun 4th 2008, 04:09 AM #5

- Joined
- Jan 2008
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Find the exact Value:

First let

If you recall basic trigonometric ratios, tangent = in this case.

Now we know that the opposite side is when the adjacent side is

Using Pythagoras's theorem, we can deduce that the hypotenuse is

=

You might want to draw a triangle if it helps you to visualise

- Jun 5th 2008, 01:06 PM #6

- Joined
- May 2008
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