Inverse Tangent equation
Got a bit of a problem,
I have an equation of a curve
and i want to find out values of x where y equals zero.
I differentiated my equation so i could find the peak if that helps anyone.
dy/dx = (c*d/(1+(d(x+e))^2))-1
Thanks in advance,
Solving for x has nothing to do with the derivative (unless you are trying something like Newton's method to approximate it.) This equation cannot be solved exactly as it stands. (There may be some specific values of c, d, and e such that it can be, but I can't think of any at the moment.)
Originally Posted by ajwillshire