Sec, Cosec, Cot

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• May 24th 2008, 03:14 AM
jarald83
Sec, Cosec, Cot
how to calculate the following value?
Cosec 30°
cot 60°
sec 310°
cosec 120° °
cot 600°
and -cot 130° (Doh)(Crying)
• May 24th 2008, 03:44 AM
wingless
$\tan x = \frac{\sin x}{\cos x}$

$\cot x = \frac{\cos x}{\sin x}$

$\csc x = \frac{1}{\sin x}$

$\sec x = \frac{1}{\cos x}$
• May 24th 2008, 03:58 AM
nandu11
u need to know the simple sin, cos and tan trigo ratios for 0, 30, 45, 60 and 90 to do these types of questions and then use the formulas like cosecx=1/sinx, cotx=cosx/sinx etcc