2Sin^2θ-1=0 I dunno how to do this cuz of the square any help would be appreciated.
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$\displaystyle 2\sin^{2} \theta - 1 = 0$ $\displaystyle \text{Let } x = \sin \theta .$ You get: $\displaystyle 2x^{2} - 1 = 0$ Would you able to solve it like this ?
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