Thread: Trig Equation

2Sin^2θ-1=0
I dunno how to do this cuz of the square
any help would be appreciated.

$\displaystyle 2\sin^{2} \theta - 1 = 0$

$\displaystyle \text{Let } x = \sin \theta .$

You get: $\displaystyle 2x^{2} - 1 = 0$

Would you able to solve it like this ?

The given informations related to mathematics is very useful to me. thank u for your informations.

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detta

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