1. ## Trigonometric modelling

All help much appreciated, sorry for poor set out of equation.

The height of water(h metres) on a pier pylon is given by:
h=2sin((pi/12)*t)+4, where t is given in hours after midday.What is the height of the water at:
a)2pm
b)6am the next morning

2. Originally Posted by ollieman
All help much appreciated, sorry for poor set out of equation.

The height of water(h metres) on a pier pylon is given by:
h=2sin((pi/12)*t)+4, where t is given in hours after midday.What is the height of the water at:
a)2pm
b)6am the next morning
2pm is 2 hours after midday so t=2
giving us
$h=2\sin (\frac{\pi}{6})+4$

$h=2(\frac{1}{2})+4=5$

I'll leave you to do b, but remember at 6am the next morning it going to be 18 hours after midday