This has been alluding me for a week and I am now down to the wire Prove that (sin^2(x)) / (1-cos(x)) equals (sec(x)+1)/(sec(x)) any help,hints,clues or outright answers would be appreciated! Thanks, mj
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Originally Posted by maryjane This has been alluding me for a week and I am now down to the wire Prove that (sin^2(x)) / (1-cos(x)) equals (sec(x)+1)/(sec(x)) any help,hints,clues or outright answers would be appreciated! Thanks, mj Consider the ...........Pythagorean identity ..........Numerator was the difference of two squares ..........................cancel .....................algebraic manipulation ...........................combine the fractions Thus, , as desired
Originally Posted by maryjane This has been alluding me for a week and I am now down to the wire Prove that (sin^2(x)) / (1-cos(x)) equals (sec(x)+1)/(sec(x)) any help,hints,clues or outright answers would be appreciated! Thanks, mj we know that and we also know that so So now subbing we get Cancelling the left side and splitting the left we get now we know that and so imputting back in gives
well, well, well.... I now feel like an idiot thank-you both! mj
Originally Posted by maryjane well, well, well.... I now feel like an idiot thank-you both! mj *spider-man voice*Mary Jane! hang On! you're welcome ..........that's Kriz's icon
haha one more question I have...how do we get sec(x) + 1 sec(x) sec(x) from the 1 + cos(x) ... I realize we can sub the first part for the 1 but how do we sub 1 sec(x) from cos(x) ? I am obviously missing something (i wish i could find it) mj
Originally Posted by maryjane haha one more question I have...how do we get sec(x) + 1 sec(x) sec(x) from the 1 + cos(x) ... I realize we can sub the first part for the 1 but how do we sub 1 sec(x) from cos(x) ? I am obviously missing something (i wish i could find it) mj If you are takling about how its because the rest I showed in my repsonse
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