Hello, Jigglypuff!
Yet another approach . . .
There are permutations of the six letters.Each permutation of the letters in is written on a slip of paper
and tossed into a bowl. One slip is drawn at random.
What is the probability that the letter will appear in the last position?
. . Hence, there are 720 slips of paper in the bowl.
If is last: .
. . the other 5 letters can be arranged in ways.
Hence, there are 120 slips with in the last position.
Therefore: .