Each permutation of the letters in THEORY is written on a slip of paper and tossed into a bowl. One slip is drawn at random, what is the probability that the letter T willappear in the last position?

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- May 18th 2008, 05:15 PMJigglypuffPermutation of theory
Each permutation of the letters in THEORY is written on a slip of paper and tossed into a bowl. One slip is drawn at random, what is the probability that the letter T willappear in the last position?

- May 18th 2008, 05:31 PMUnenlightened
THEORY... Six letters.

Only one can come last at any given time.

There's a one in six chance that this will be 'T'.

So: 1/6.

That's probably the simplest way of looking at it...

You could also say that you had:

5/6 * 4/5 * 3/4 * 2/3 * 1/2 * 1/1 = 1/6.

I think... - May 18th 2008, 07:59 PMSoroban
Hello, Jigglypuff!

Yet another approach . . .

Quote:

Each permutation of the letters in is written on a slip of paper

and tossed into a bowl. One slip is drawn at random.

What is the probability that the letter will appear in the last position?

. . Hence, there are 720 slips of paper in the bowl.

If is last: .

. . the other 5 letters can be arranged in ways.

Hence, there are 120 slips with in the last position.

Therefore: .