i need help with this one...

tanx-tan(x-y)= tany

1+tanx*tan(x-y)

Printable View

- Jun 1st 2005, 09:47 AMzamorakk0
i need help with this one...

__tanx-tan(x-y)__= tany

1+tanx*tan(x-y) - Jun 1st 2005, 04:05 PMvms
$\displaystyle \[\frac{tan(A) - tan(B)}{{1 + tan(A)*tan(B)}} = tan(A - B)$