Find the exact value of sin2θ given that cosθ= -12/13 and θ is in Quadrant II.
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Originally Posted by kelsey3 Find the exact value of sin2θ given that cosθ= -12/13 and θ is in Quadrant II. tells us that Since we know that is in QII where sine is positive, we know to use the + sign. Now and you can take it from there. -Dan
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