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Math Help - Simple question??

  1. #1
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    Mar 2008
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    Simple question??

    Hi guys

    Its revision time, and I've been going through previous papers for the module. One cropped up asking for an angle, given sin^2(x)=0.64. I know how I'd go about it if it was simply sin... but i just dont know the inverse of sin^2 (x)!!
    None of my coursemates know either, but I cant ignore it and hope it doesnt come up really!

    Any help on the matter would be appreciated!

    Thanks
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  2. #2
    Super Member flyingsquirrel's Avatar
    Joined
    Apr 2008
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    Hi

    When solving something like X^2=100, you find the solutions saying that X=\pm\sqrt{100}=\pm10. You're in this situation here, except that X=\sin x and that 100 has been replaced by 0.64 :

    \sin^2x=0.64 \Leftrightarrow \sin x=\pm \sqrt{0.64}=\pm 0.8

    It gives you two equations to solve, good luck !
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  3. #3
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    Genius, cheers!

    I was looking for an identity
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