if z=5i and w=(-9*sqrt(2))/2 + (9*sqrt(2))/2
determine z/w in polar form
Could some one please get me started I dont know how you can find the angle formed when z=5i?
dont I need a real part not just imaginary
Thanks
Hello,
Isn't it w=(-9*sqrt(2))/2 + (9*sqrt(2))/2 i ?
First of all, multiply above and below by the conjugate of wdetermine z/w in polar form
I think this would come laterCould some one please get me started I dont know how you can find the angle formed when z=5i?
Try to get to the step I mentioned.
If you have z=5i, it means that z=0+5idont I need a real part not just imaginary
$\displaystyle |z|=5$
$\displaystyle 5i=5(\cos(\theta)+i \sin(\theta)$
So we can see that $\displaystyle \cos(\theta)=0$ and $\displaystyle \sin(\theta)=1$
there is a similar question asked previously have a look:
http://www.mathhelpforum.com/math-he...-form-c-n.html