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Math Help - trig

  1. #1
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    Joined
    Apr 2008
    Posts
    4

    trig

    I'd really appreciate it if someone could help me with these problems. I just don't even know where to start. Thanks so much!

    1. use the given values to evaluate the remaining trig functions:
    cscx = -5
    cosx < 0

    2. solve for x: [0,2pi] Sin 3x= 1/2

    3. rewrite the expression not in fractional form: 1/(csc x + 1)

    4. Verify the identity (work on one side only if possible):
    sec x - cos x = sin x tan x
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  2. #2
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    Joined
    Nov 2007
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    Well the last question's solution struck to my mind first.
    Given to prove:
    secx-cosx=sinxtanx
    Taking the left hand side:
    secx-cosx
    =(1/cosx)-cosx
    =(1-cos^2x)/cosx
    =sin^2x/cosx ((1-cos^2x)=sin^2x)
    =(sinx/cosx)sinx
    =sinxtanx
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  3. #3
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    Joined
    Apr 2008
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    thank you.. i'm not really following towards the end though.. ugh I'm so frustrated! Can anyone help me with the others../??
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