You may conclude now.
The original equation is: " 1/1-cosx - 1/ 1+secx = csc^2x + cot^2x "
These are the steps i've used so far:
= 1/1-cosx (1+cosx/1+cosx) - 1/1+secx (1-secx/1-secx) ---multiply by the conjugate
= 1+cosz/sin^2x + 1-secx/tan^2x
Thats as far as i've been able to get.
Any help would be greatly appreciated!
ok, when you multiply the left side by cosx/cosx, i see how that would give you cosx as the numerator, but wouldnt that leave you with 1+secxcosx as the denominator, how does that eqaul 1+cosx? And after that step to get 1/1-cosx - cosx/1+cosx are you multiplying both sides by their conjugate to get a common denominator so that you can combine them to 1-cos^2x?
Thanks for all the help, i just learned this a few days ago and am still trying to understand all the transformations and steps involved.