Okay, $\displaystyle cos \theta = -0,36467$
Let's see where cos is negative.
That would be the second and third quadrants.
Now let's calculate a reference angle.
$\displaystyle x = cos ^{-1} (0,36467)$ Why did I drop the negative? Because we just determined where it will be negative. All we want now is a reference angle, which we will call $\displaystyle x$.
$\displaystyle x = 68,61272464$
Now substitute $\displaystyle x$ into the second and third quadrants.
Quadrant 2:
$\displaystyle \theta = 180 - x = 111,3872$
Quadrant 3:
$\displaystyle \theta = 180 + x = 248,6127$
I'm sure you can handle the rounding