Thread: trigonometric functions

I've been working on this problem for awhile now but I think it's easier than I'm making it seem. Here's what I have so far:

3sec^2x = 4
sec^2x = 4/3
secx = sqrt 4/3

It seems right to me but of course sqrt 4/3 isn't a proper answer, since it's not within the domain of sec x. Am I doing this right, and is the answer 'undefined,' or is there something wrong? Please help me, thanks.

(by taking the reciprical)




I'm not sure what made you lead to the conclusion that your answer leads to sec x being undefined ..

Originally Posted by o_O

(by taking the reciprical)




I'm not sure what made you lead to the conclusion that your answer leads to sec x being undefined ..

Ahh, thank you so much! I put it in my calculator and it gave me an error. My teacher's right, then, when she says we shouldn't depend on them.