# Thread: Solving Linear Trig Equations

1. ## Solving Linear Trig Equations

I have many questions with this as i am genuinely confused.

First, how should a question like this be answered.

The domain is 0 to 360 degrees. the question is

3 sin x=sin x + 1

Second,

The average monthly temperature of Littletown can be modelled by the function T(t)=14.6sin 0.5(t-1) + 9.15 where T is the temperature in degrees celsius and t=0 represents January, t=1 represents February 1, and so on.

a, In which month is the average temperature the highest? the lowest?

b, Use the model to predict when the temperature is 0 degrees celsius

c, When is the temperature 20 degrees celsius.

For this one can you show me what i need to do to get the proper table of values?

Thanks alot.

2. Originally Posted by FORK
I have many questions with this as i am genuinely confused.

First, how should a question like this be answered.

The domain is 0 to 360 degrees. the question is

3 sin x=sin x + 1

Second,

The average monthly temperature of Littletown can be modelled by the function T(t)=14.6sin 0.5(t-1) + 9.15 where T is the temperature in degrees celsius and t=0 represents January, t=1 represents February 1, and so on.

a, In which month is the average temperature the highest? the lowest?

b, Use the model to predict when the temperature is 0 degrees celsius

c, When is the temperature 20 degrees celsius.

For this one can you show me what i need to do to get the proper table of values?

Thanks alot.
Should this be $3\sin^2(x)=\sin(x)+1$?
if not $3\sin(x)=\sin(x)+1\Rightarrow{2\sin(x)=1}$

then $x=arcsin\bigg(\frac{1}{2}\bigg)=\frac{\pi}{6}$\

and what other angle gives 1/2?

3. Originally Posted by Mathstud28
Should this be $3\sin^2(x)=\sin(x)+1$?
if not $3\sin(x)=\sin(x)+1\Rightarrow{2\sin(x)=1}$

then $x=arcsin\bigg(\frac{1}{2}\bigg)=\frac{\pi}{6}$\

and what other angle gives 1/2?
Its this one. $3\sin(x)=\sin(x)+1\Rightarrow{2\sin(x)=1}$

And it gives me 0.034 when i do it but my book says 0.52?