How do you get $\displaystyle \frac{x-xcosx}{2sinx-2xcosx}$ to be.... $\displaystyle \frac{1+xsinx-cosx}{2xsinx}$ any ideas?
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I do not understand what you are asking. Those two expressions are not equal. A simple graphing utility will verify that fact. What are you asking?
Thats all I needed to know, because I thought through a process of trig formulas you could attain that 2nd form, but thank you fot telling me they are not equivalent
Originally Posted by Mr. Engineer but thank you fot telling me they are not equivalent If they were the same the graph of their difference would be zero.
Originally Posted by Mr. Engineer How do you get $\displaystyle \frac{x-xcosx}{2sinx-2xcosx}$ to be.... $\displaystyle \frac{1+xsinx-cosx}{2xsinx}$ any ideas? I DONT KNOW CAN U EXPLAIN ME PLEASE
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