# Help with an explanation

• Apr 28th 2008, 01:14 PM
Mr. Engineer
Help with an explanation
How do you get $\displaystyle \frac{x-xcosx}{2sinx-2xcosx}$
to be....
$\displaystyle \frac{1+xsinx-cosx}{2xsinx}$

any ideas?
• Apr 28th 2008, 01:56 PM
Plato
I do not understand what you are asking.
Those two expressions are not equal.
A simple graphing utility will verify that fact.
• Apr 28th 2008, 02:04 PM
Mr. Engineer
Thanks
Thats all I needed to know, because I thought through a process of trig formulas you could attain that 2nd form, but thank you fot telling me they are not equivalent
• Apr 28th 2008, 02:20 PM
Plato
Quote:

Originally Posted by Mr. Engineer
but thank you fot telling me they are not equivalent

If they were the same the graph of their difference would be zero.
• May 1st 2008, 02:00 AM
ravali reddy
Quote:

Originally Posted by Mr. Engineer
How do you get $\displaystyle \frac{x-xcosx}{2sinx-2xcosx}$
to be....
$\displaystyle \frac{1+xsinx-cosx}{2xsinx}$

any ideas?

I DONT KNOW CAN (Doh)U EXPLAIN ME PLEASE