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Math Help - Complex Numbers to polar..

  1. #1
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    Complex Numbers to polar..

    Could use some help on this... as i remember it seemed pretty easy, but doesnt it always?

     1 - \sqrt 3i \longrightarrow polar

     \sqrt 5 + i \longrightarrow polar

     2(cos (\pi/6) + sin (\pi/6i) \longrightarrow rect

    some direction would be helpful. thanks...
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  2. #2
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    Quote Originally Posted by cjmac87 View Post
    Could use some help on this... as i remember it seemed pretty easy, but doesnt it always?

     1 - \sqrt 3i \longrightarrow polar

     \sqrt 5 + i \longrightarrow polar

     2(cos (\pi/6) + sin (\pi/6i) \longrightarrow rect

    some direction would be helpful. thanks...
    If you have a complex number z in the form of a +bi, then the polar conversion is z = r(\cos( \theta ) + i\sin( \theta)) and a=r\cos( \theta ) and b=r\sin( \theta ), where r=\sqrt{a^2+b^2}. If you draw out a point on the complex plane and work with the right triangle it makes, you can derive these or verify them easily.
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