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Thread: COnverting rectangular equations to polar (and vice versa)

  1. April 27th 2008, 11:28 PM #1
    cjmac87
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    COnverting rectangular equations to polar (and vice versa)

    i understand the concepts of converting single coordinates, however im confused on how and why on some these parts.... hopfully i could get a little more help on this...

    Convert equations to rect.

    r=4

    rsin(\theta) = -2

    \theta = pi/3

    r = sin(\theta) - cos (\theta)

    Convert Equations to polar

    2x^2 + 2y^2 = 3
    y = 3

    I already got a hang of some of the basics of this... but a little further explanation owuld be much appreciated so i can hopeuflly ace this coming quiz. ty
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  2. April 27th 2008, 11:49 PM #2
    Danshader
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    the relation between polar and rectangle:

    x = r \cos (\theta)
    y = r \sin (\theta)
    r^2 = x^2 + y^2

    for example:

    2x^2 + 2y^2 = 3<br />
    2(x^2 + y^2) = 3
    2r = 3
    r=\frac {3}{2}

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  3. April 28th 2008, 12:22 AM #3
    Jameson
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    OP, the advice here applies to your other thread as well.
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  4. April 28th 2008, 08:06 AM #4
    cjmac87
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    ok, this is more of the material my teacher wants.... can anyone please check on correctness and help me fix my errors.


    : y=1.732x using tan(y/x)

    : r^2 = y^2 - x^2

    rsec(\theta) = -4

    -4 = x

    r = cos(\theta)

    y=x

    Convert Equations to polar

    ===> 2cos(\theta)^2 + 2sin(\theta)^2 = 3<br />

    please tell me whats right, whats right, and what i can fix.

    y = -3 \longrightarrow sin^2 = - 3
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