hey people, here's the question that i have absolute no idea to answer...

A triangle $ABC$ is right-angled at $B$
$D$ is the point on $AC$ such that $BD$ is perpendicular to $AC$
Let Angle $BAC$ = $x$
You are given that $6AD + BC = 5AC$

Find $x$
I had drawn the diagram on my book but i have no idea what to do to find $x$
I had drawn the diagram on my book but i have no idea what to do to find $x$