Hello just got a couple problems I'm stuck on. Seeking some help. csc^-1x = sin^-1 (1/x) and sec^-1(x) = cos^-1 (1/x)
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Let $\displaystyle y = \sin^{-1} x$. So: $\displaystyle \sin y = x$ $\displaystyle \frac{1}{\sin y} = \frac{1}{x}$ $\displaystyle \csc y = \frac{1}{x}$ $\displaystyle y = \csc^{-1} \left(\frac{1}{x}\right)$
Would the second question have the same set up as the previous. Show that the following identity is true sec-1x = cos-1 (1/x) let y= cos^-1 cosy=x 1/cosy=1/x secy=1/x y= sec^-1 (1/x)
Yep. Don't doubt yourself!
Thanks. I will work on that not doubting myself part as I continue to work through some more of these.
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